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(zOu789)RuanMei(Pixiv)[AI Generated]

Misc
(Disowned)
Posted:2026-02-20 09:19
Parent:None
Visible:Yes
Language:Japanese  
File Size:240.9 MiB
Length:84 pages
Favorited:319 times
Rating:
38
Average: 4.29

Showing 1 - 20 of 84 images

<12345>
<12345>
Posted on 20 February 2026, 09:19
Uploader Comment
https://www.pixiv.net/users/123465439
好耶是新衣服的阮梅女士😍这对白白软软的奶香大包子能忍住不吃的也是神人了👍受不了了我TM直接开导🥵
(sinx)' = cosx
(cosx)' = - sinx
(tanx)'=1/(cosx)^2=(secx)^2=1+(tanx)^2
-(cotx)'=1/(sinx)^2=(cscx)^2=1+(cotx)^2
(secx)'=tanx·secx
(cscx)'=-cotx·cscx
(arcsinx)'=1/(1-x^2)^1/2
(arccosx)'=-1/(1-x^2)^1/2
(arctanx)'=1/(1+x^2)
(arccotx)'=-1/(1+x^2)
(arcsecx)'=1/(|x|(x^2-1)^1/2)
(arccscx)'=-1/(|x|(x^2-1)^1/2)
(sinhx)'=coshx
(coshx)'=sinhx
(tanhx)'=1/(coshx)^2=(sechx)^2
(coth)'=-1/(sinhx)^2=-(cschx)^2
(sechx)'=-tanhx·sechx
(cschx)'=-cothx·cschx
(arsinhx)'=1/(x^2+1)^1/2
(arcoshx)'=1/(x^2-1)^1/2
(artanhx)'=1/(x^2-1) (|x|<1)
(arcothx)'=1/(x^2-1) (|x|>1)
(arsechx)'=1/(x(1-x^2)^1/2)
(arcschx)'=1/(x(1+x^2)^1/2)
Posted on 20 February 2026, 11:00 by:   201314*    PM
Score +15
?这也能求导,多少有点离谱了

咏春就很适合古风美人
Last edited on 21 February 2026, 15:18.
Posted on 02 March 2026, 10:56 by:   djyzdys    PM
Score +6
符合你的ID
Posted on 03 March 2026, 13:13 by:   JSMR    PM
Score +6
有没有这个作者其他的作品

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